Five kilograms of oranges contained 98% of water. If the next day the concentration of water decreased by 2%, what online casinos was the new weight of the oranges, in kilograms?

(A) 4.9

(B) 4.8

(C) 2.5

(D) 2

(E) 0.2

Five kilograms of oranges contained 98% of water. If the next day the concentration of water decreased by 2%, what online casinos was the new weight of the oranges, in kilograms?

(A) 4.9

(B) 4.8

(C) 2.5

(D) 2

(E) 0.2

4.9

A

5 – (5*0,02)= 4,9

(C) 2.5

Artem, (C) это правильный ответ. Поделитесь, пожалуйста, своим решением

C

Larisa, поделитесь, пожалуйста, как вы пришли к правильному ответу

концентрация уменьшилась на 2% значит:

0.96 x 5= 4.8 kg

5kg*98%-(98%*2%)=4.8

Рассудите нас уже!

Всем спасибо за мысли! Еще немного терпения

1) The concentration of water decreased by 2%, not by 2 percentage points. Thus, we should calculate the decrease of the concentration of water in such a way: 98% * 2% = 1,96%

2) The decrease of water in kilograms: 5 * 1,96% = 0,098

3) The new weight of the oranges in kilograms: 5 – 0,098 = 4,902 ≈ 4,9

The correct answer is (A)

B

Еще один вариант решения:

Total amount × percent decrease = decrease in amount

Total amount – decrease in amount = net result

5 × 0.02 = 0.1

5 – 0.1 = 4.9

(A)

4,9=(5*96%)/98%

4.9

A) 4.9 (around)

Great question, Olga!

and what is your answer, Charles?

Answer C.

5 kg= 98% of water and 2% of peel for instance.

2%= 100 gm.

Then we have 96 % of water, hence 4 % of peel.

If our 100gm of peel is 4% of oranges now, so the weight of oranges should be 2,5 kg.

That’s the correct answer and solution! Thank you, victoria!

If you have another approach or any questions, please, share